Recently we faced a problem that we need to round-up a number to greatest 10s place.

For ex: we needed to round-up a number as follows

1023 -> 2000

37911 -> 40000

912345 –> 1000000

First we checked Math.Round(). But it didn’t solve our problem. Math.Round() supports only rounds a value to the nearest integer or to the specified number of fractional digits. Further checking we come up a solution by using Math.Ceiling() method.

Math.Ceiling()returns the smallest integral value that is greater than or equal to the specified double-precision floating-point number.

For ex:

Math.Ceiling(7.3) -> 8

Math.Ceiling(7.64) -> 8

Math.Ceiling(0.12) -> 1

Below is the solution we came up

decimal[] values = { 1023, 37911, 23000, 1234, 912345 }; foreach (var value in values) { //// get the lenght of the 10s places; var length = (int)Math.Log10((double)value); //// using Math.Pow() calculate the power of 10s var power = Math.Pow(10, length); //// var roundadValue = Math.Ceiling(1023 / 1000) * 1000; var roundadValue = Math.Ceiling(value / (decimal)power) * (decimal)power; Console.WriteLine("Value:{0} Rounded Value:{1}", value, roundadValue); }

## The Logic

Math.Ceiling(value / (decimal)power) * (decimal)power; var roundadValue = Math.Ceiling(1023 / 1000) * 1000;

so, for any number, fist compute power of 10s and then it use for above calculation to get the results.